2 cos 165° cos 75° + 4 cos 127,5° sin 97,5°
Tentukan nilai dari 2 cos 165° cos 75° + 4 cos 127,5° sin 97,5°!
Jawab:
2 cos 165° cos 75° + 4 cos 127,5° sin 97,5°
= cos (165° + 75°) + cos (165° – 75°) + 2 [sin (127,5° + 97,5°) – sin (127,5° – 97,5°)]
= cos 240° + cos 90° + 2(sin 225° – sin 30°)\
= - ½ + 0 + 2(-1/2√2 – 1/2)
= - ½ – √2 – 1
= -3/2 – √2
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