Jika f(x) = 3 sin (2x – π), nilai f’(½π) =
Jika f(x) = 3 sin (2x – π), nilai f’(½π) = ….
A. 6
B. 3
C. 3/2
D. 0
E. -3/2
Pembahasan:
f(x) = 3 sin (2x – π)
f'(x) = 6 cos (2x – π)
f’(½π) = 6 cos (2(½π) – π)
= 6 cos 0
= 6 (1)
f’(½π) = 6
Jawaban: A
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